WebThe value of tan 6 * tan 42*tan 66*tan 78 is Byju's Answer Standard X Mathematics Standard Values of Trigonometric Ratios The value of ... Question The value of … Webtana+tan (60+a)-tan (60-a)=3tan3a Let's use the sum-of-angles formula for tangent, tan (x+y) = (tanx + tany)/ (1 - tanx tany), along with tan60º = √3 tan (60º ± A) = (√3 ± tanA) / (1 ∓ (√3) tanA) = (1 ± (√3) tanA) (√3 ± tanA) / (1 - 3 tan²A) = (3 ± 4 tanA + (√3) tan²A) / (1 - 3 tan²A) tanA + tan (60º + A) - tan (60º - A)
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WebJul 3, 2013 · tan6 * tan54 * tan66 * tan18 * tan42 * tan78 = tan18 * tan54 tan6 * tan66 * tan42 * tan78 = 1 PROVEN. 1 ; Sorry but it is not the answer to my query, geethanjali. I … Web求下列各式的值(1)tan6°tan42°tan66°tan78°,(2)tan3°tan17°tan23°tan37°tan43°tan57°tan63°tan77°tan83°tan27°. subway meridian ms frontage rd
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WebIf A=tan 6 tan 42 and B=cot 66 cot 78, then A/B=? A=tan6°tan42° and B=cot66°cot78° A/B=tan6°tan42°tan66°tan78° Using tan (60-x)tanxtan (60+x)=tan3x for x=18° we get … WebMay 4, 2015 · Find an answer to your question The value of tan6°tan42°tan66°tan78° is. satishpaladi11 satishpaladi11 04.05.2015 Math Secondary School answered • expert verified ... Tan42 Tan 78 = Tan (60 - 18) * Tan (60 + 18) = (Tan 60 - tan 18) / (1+tan60 tan18) * (tan60 + tan18) / (1 - Tan60 tan18) WebA=tan6°tan42° and B=cot66°cot78° A/B=tan6°tan42°tan66°tan78° Using tan(60-x)tanxtan(60+x)=tan3x for x=18° we get tan42°tan18°tan78°=tan54° for x=6° we get … subway meridian st huntsville al